Questions d'entretiens - Java developer

19 k

Questions d'entretien pour Java Developer partagées par les candidats

Principales questions d'entretien

Trier: Pertinence|Populaires|Date
Naaptol
On a demandé à un Junior Java Developer...10 janvier 2018

attributes of <tr> tag

41 réponses

please let me know if anyone got Job

36. If you get call then follow this interview experience

How many of you waiting after 3rd round

Afficher Plus de réponses
EPAM Systems

Coding test: 1. Given a string, find out if there's repeat characters in it. 2. SQL. Given a Customer table and a Payment table (with Customer ID as primary and foreign key), write a query to output a list of customers who have not paid their bills in the last 3 months.

15 réponses

Did well on the first Java coding test. Solution using Hashset. Not so well on the SQL query. Able to give a query, but a few errors in it I am sure. Also there was a second questions regarding the SQL query, which we didn't have time to get to. So that was another bad thing. I am pretty sure I did not pass. But good learning experience. Moins

import java.util.*; public class test { public static void main(String[] args) { String str = "abdc"; char[] arr = str.toCharArray(); HashSet set = new HashSet(); for (char i : arr ) { set.add(i); } if((set.size()) == (arr.length)) System.out.println("unique character"); else System.out.println("repetition"); } } Moins

No

Afficher Plus de réponses
Oracle

Write a program to print * * * * * * * * * * * * * * * * * * * * * * * * * * * * * with minimum number of variable use

12 réponses

class StarPrint { public static void main (String[] args) throws java.lang.Exception { int i = 0, j = 0; for( i = 5; i &gt; 0; i-- ){ for( j = 0; j &lt; 5 - i; j++) System.out.print(" "); for( j = 0; j &lt; i; j++ ) System.out.print("* "); System.out.println();} for( i = 3; i &lt;= 6; i++ ){ for( j = 0; j &lt;= 5 - i; j++) System.out.print(" "); for( j = 1; j &lt; i; j++ ) System.out.print("* "); System.out.println(); } } } Moins

public class Check { public static void main(String[] args) { int limit = 5; // Specify the number of lines as limit and check output int i=0,j=0; for(i=0;ilimit-i;j--)System.out.print(" "); for(j=limit;j&gt;i;j--)System.out.print("* "); System.out.println(); } j=limit; for(;limit&gt;1;limit--){ for(i=2;ilimit-2;i--)System.out.print("* "); System.out.println(); } } } Moins

In the previous solution, the LESS THAN and GREATER THAN symbols have nit been parsed. public class Check { public static void main(String[] args) { int limit = 9; int i=0,j=0; for(i=0;i limit-i;j--)System.out.print(" "); for(j=limit;j &gt; i;j--)System.out.print("* "); System.out.println(); } j=limit; for(;limit &gt; 1;limit--){ for(i=2;i limit-2;i--)System.out.print("* "); System.out.println(); } } } Moins

Afficher Plus de réponses
WebKul

Write a program for odd input the pattern output will as below n=1 *-* n=3 ***** *** *---* *** *****

11 réponses

import java.util.Scanner; public class Pattern{ public static void main(String[] args) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); for(int i=n;i&gt;=2;i--){ for(int j=1;j&lt;=2*n-(i-1);j++){ System.out.print(" "); } for(int k=1;k&lt;=2*i-1;k++){ System.out.print("*"); } System.out.println(); } for(int i=1;i&lt;=n-1;i++){ System.out.print(" "); } System.out.print("*"); for(int i=1;i&lt;=n;i++){ System.out.print("-"); } System.out.print("*"); System.out.println(); for(int i=2;i&lt;=n;i++){ for(int j=1;j&lt;=n-i;j++){ System.out.print(" "); } for(int k=1;k&lt;=2*i-1;k++){ System.out.print("*"); } System.out.println(); } } } Moins

import java.util.Scanner; class New3 { public static void main(String ... args) { Scanner sc =new Scanner(System.in); int n=sc.nextInt(); for(int j=n,p=1;j&gt;=2;j--,p++) { for(int i=1;i&lt;=n+p;i++) System.out.print(" "); for(int k=1;k&lt;=2*j-1;k++) System.out.print("*"); System.out.println(""); } for(int i=1;i&lt;=n-1;i++) System.out.print(" "); System.out.print("*"); for(int i=1;i&lt;=n;i++) System.out.print("-"); System.out.print("*"); System.out.println(""); int q=n-2; for(int j=2;j&lt;=n;j++) { for(int i=1;i&lt;=q;i++) System.out.print(" "); q--; for(int k=1;k&lt;=2*j-1;k++) System.out.print("*"); System.out.println(""); } } } Moins

import java.util.Scanner; public class webu { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("enter the no"); int n=sc.nextInt(); for (int i = n; i &gt;1; i--) { for(int j=1;j1){ for (int l =1 ; l &lt;=2*i-1; l++) { System.out.print("*"); } System.out.println(" "); } } } } Moins

Afficher Plus de réponses
Naaptol

written test on basic java you can crack if you are average concept in java.

10 réponses

But what is the need of exam no result came 2 months have passed i suggest never go and waste your time. Moins

you are right . I have never seen any interview experience that got job offer . at every end of year they have walkin drive . Thats look suspicious . At everytime when you go for interview they ask for reference. It might be true that they hire people who have strong refrence Moins

Yes I got call. May be they call only those people who cracks Aptitude They may have high cut off. Moins

Afficher Plus de réponses
Atlassian

A company uses a format to exchange messages with us. You need to validate the input. The character encoding ASCII. Valid characters are between 0x20 (space) and 0x7E (~). write validate function to generate valid output or the error message.

9 réponses

public static void printValidMassage(){ String msg="204a6176617e"; String msg1=convertHextoChars(msg); boolean isValid=(msg1.startsWith(" ") &amp;&amp; msg1.endsWith("~")) ? true : false; } private static String convertHextoChars(String hex) { StringBuffer sb = new StringBuffer(); for (int i=0; i Moins

public static void printValidMassage(){ String msg="204a6176617e"; String msg1=convertHextoChars(msg); boolean isValid=(msg1.startsWith(" ") &amp;&amp; msg1.endsWith("~")) ? true : false; System.out.println(isValid); } private static String convertHextoChars(String hex) { StringBuffer sb = new StringBuffer(); for (int i=0; i Moins

for (int i=0; i

Afficher Plus de réponses
WebKul

take input from user...3,5,7 etc and draw a pattern if input is 3 then *** *** * * *** * * * if input is 5 then ***** ***** * * * * * * ***** * * * * *

9 réponses

code for c language #include #include int main() {int n=7,i,j,l,k,m; for(i=1;i&lt;=n;i++) printf("*"); printf(" "); for(i=1;i&lt;=n;i++) printf("*"); printf("\n"); for(j=1;j&lt;=n-2;j++) { for(k=1;k&lt;=n-1;k++) printf(" "); printf("*"); printf(" "); printf("*"); printf("\n"); } for(i=1;i&lt;=n-1;i++) printf(" "); for(i=1;i&lt;=n;i++){ printf("*");} printf("\n"); for(i=1;i&lt;=n;i++) { for(j=1;j&lt;=n;j++) printf(" "); printf("*"); printf("\n"); } return 0; } Moins

/* if input is 3 then *** *** * * *** * * * if input is 5 then ***** ***** * * * * * * ***** * * * * * */ import java.util.Scanner; public class Pattern3 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n=sc.nextInt(); for(int i=1; i&lt;=2; i++){ for(int j=1; j&lt;=n; j++){ System.out.print("*"); }System.out.print(" "); }System.out.println(); for(int i=1; i&lt;=n-2; i++){ for(int j=1; j&lt;=n-1; j++){ System.out.print(" "); }System.out.println("* *"); } for(int i=1; i&lt;=(n+1)/2; i++){ System.out.print(" "); } for(int i=1; i&lt;=n; i++){ System.out.print("*"); }System.out.println(); for(int i=1; i&lt;=n; i++){ for(int j=1; j&lt;=n; j++){ System.out.print(" "); }System.out.println("*"); } sc.close(); } } Moins

check this import java.util.Scanner; public class MyClass { public static void main(String args[]) { Scanner sc =new Scanner(System.in); int n=sc.nextInt(); for(int i=0;i&lt;2;i++){ for(int j=0;j Moins

Afficher Plus de réponses
Mobicule

If you add an element at a[1] position in arreylist and access a[2] element,what will happen?

9 réponses

Let arraylist contains {5,6,4,3,1} If you add 2 at 0th position then arraylist become {2,5,6,4,3,1} So according to question you will get old element of a[1] at a[2]'s position Moins

We will get runtime exception:ArrayIndexOutOfBoundException

Let arraylist contains {5,6,4,3,1} If you add 2 at 0th position then arraylist become {2,5,6,4,3,1} So according to question you will get old element of a[1] at a[2]'s position Moins

Afficher Plus de réponses
WebKul

The first question was to print pattern that is n=1 *** n=3 * * *** *** ************ *** *** * * n=5 * * *** *** ***** ***** ******************* ***** ***** *** *** * *

9 réponses

I don't understand the logic of mid line.... import java.util.Scanner; /* 1 *** 3 * * *** *** ************ *** *** * * 5 * * *** *** ***** ***** ******************* ***** ***** *** *** * * */ public class Pattern1 { public static void main(String[] args) { Scanner sc =new Scanner(System.in); int n=sc.nextInt(); if(n&gt;1){ for(int i=1; i1){ for(int i=(n+1)/2; i&gt;=1; i--){ for(int j=1; j&lt;=(((n+1))/2)+1-i; j++){ System.out.print(" "); } int k=0; while(k != (2*i)-1){ System.out.print("*"); k++; }k=0; System.out.print(" "); while(k!=(2*i-1)){ System.out.print("*"); k++; }k=0; System.out.println(); } } sc.close(); } } Moins

import java.util.Scanner; /* 1 *** 3 * * *** *** ************ *** *** * * 5 * * *** *** ***** ***** ******************* ***** ***** *** *** * * */ public class Pattern1 { public static void main(String[] args) { Scanner sc =new Scanner(System.in); int n=sc.nextInt(); if(n&gt;1){ for(int i=1; i1){ for(int i=(n+1)/2; i&gt;=1; i--){ for(int j=1; j&lt;=(((n+1))/2)+1-i; j++){ System.out.print(" "); } int k=0; while(k != (2*i)-1){ System.out.print("*"); k++; }k=0; System.out.print(" "); while(k!=(2*i-1)){ System.out.print("*"); k++; }k=0; System.out.println(); } } sc.close(); } } Moins

package pattern; import java.util.Scanner; public class webu1 { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("enter the no"); int n=sc.nextInt(); for(int i=1;i=1; i--) { for (int j = 0; j &lt; n-i; j++) { System.out.print(" "); } for(int k=0;k&lt;(2*i-1);k++){ System.out.print("*"); } System.out.print(" "); for(int k=0;k&lt;(2*i-1);k++){ System.out.print("*"); } System.out.println(""); } } } Moins

Afficher Plus de réponses
Systems Logic

They asked me about the Java Object - Oriented, Inheritance and Out-put the single value of the 2 dimension array

7 réponses

can you please tell me if this good company?

Could you be more specific about the questions? And could you explain how you answered their questions, please! I'm gonna have the C# interview from Systems Logic, and they're gonna ask me questions about C++. So, if you can specify the questions they asked you, it could be more helpful to me. Please!!! Moins

I have got the phone all and email from them but that's it. Did they contact you again? How did you set up the appointment with them? Moins

Afficher Plus de réponses
1 - 10 sur 18 679 Questions d'entretien

Consultez les questions posées en entretiens pour des emplois similaires