Implement Sum(3)(4)(5)=12 with javascript

Question

Utilisateur anonyme · Accepted Answer

const Sum = a => b => c => a + b + c;

Luke Schoen · Answer

```
// Lexically nested function definitions defined within enclosing function 
function Sum(arg0) {
  function Inner1(arg1) {
    function Inner2(arg2) {
      return arg0 + arg1 + arg2;
    }
    return Inner2;
  }
  return Inner1;
}
console.log(Sum(3)(4)(5));
```

Utilisateur anonyme · Answer

var sum=0; // global variable
function Sum(num){
  sum=num+sum; 
  return Sum; 
}
Sum(3)(4)(5);

Andy · Answer

addNumbers([3,4,5])
const addNumbers = (numberArray) => {
       let result = 0;
     numberArray.map(x => {
         result = result + x;
     }
     return result;
}

Tukaram Patil (Pune) · Answer

Find some generic solution.

const Sum = (p1) => (p2) => p2  ?  Sum(p1 + p2) : p1;
const result = Sum(3)(4)(5);    // also it can work for  Sum(3)(4)(5)();
console.log( typeof result === 'function' ? result(): result);

Utilisateur anonyme · Answer

Yall thinking too complicated:

var numbers = [3, 4, 5]; document.getElementById("total").innerHTML = numbers.reduce(myFunc); function myFunc(total, num) { return total + num; }

Lokesh · Answer

curried function in JS will solve this

function Sum(param1){
    return function(param2){
        return function(param3){
            return param1+param2+param3;
        }
    }
}

Sum(3)(4)(5) -->12

Mike Tatsky · Answer

const sum = function (a) {
  let closureFunc = b =>  b ? sum(a + b) : a;
  
  closureFunc.toString = () => a;
  
  return closureFunc;
}

Vinoth kumar V · Answer

Implement Sum(3)(4)(5)=12 with javascript ?

Ans: 
var sum  = function(a) {
       return function(b) {
            return a+ b;
       }
}
sum  (3)(4)(5) ;

// 12

Utilisateur anonyme · Answer

function Sum(a){
	return function(b){
		return function(c){
			return a+b+c;
		}
	}
}

abc · Answer

arrow fun undoubtedly make it pretty simple to get the result.


const Sum = a => b => b ? Sum( a + b ) : a;

console.log(Sum(3)(4)(2)(5)()); //19
console.log(Sum(3)(4)(1)()); //8

chitresh · Answer

let x = a => b =>  b ? x(a+b) : a;

Andy · Answer

Correction! Missing closing bracket plus line terminator!


0
▼
addNumbers([3,4,5])
const addNumbers = (numberArray) => {
       let result = 0;
     numberArray.map(x => {
         result = result + x;
     });
     return result;
}

Vidal Quevedo · Answer

function sum(x) {
  sum.result = (sum.result) ? sum.result += x : x;
  sum.valueOf = function() {
    return sum.result;
  }
  return sum;
}

sum(1)(2)(3); // == 6

sukumarmedidi3691172@gmail.com · Answer

ES6 Syntax:

let add = (a, b) => a + b;

console.log(add(2, 5)); 
// output: 7

const add2 = a => b => a + b;

console.log(add2(2)(5));

Rishi Raj Sisodia · Answer

var sum=0; // global variable
function Sum(num){
  return num;
}
document.write(Sum(3)+Sum(4)+Sum(5));

ES6 · Answer

const sum = (arg1) => (arg2) => (arg3) => arg1 + arg2 + arg3;

sum(1)(2)(3);

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