Question d’entretien chez Google

Write a Square Root function for a computer without floating point calculations

Réponses aux questions d'entretien

Utilisateur anonyme

24 août 2012

Use the babylonian method http://en.wikipedia.org/wiki/Methods_of_computing_square_roots#Babylonian_method

3

Utilisateur anonyme

18 août 2012

Use fractions (=2 integers) and the Babylonian/Newtonian approach: X(n+1) = (X(n)^2 + N) / (2 * X(n))

1

Utilisateur anonyme

6 août 2012

Perhaps using binary search will work.

2

Utilisateur anonyme

8 août 2012

By approximation. Star with a = 1 and check if a*a is > N. If so you return a-1 else a++ and move forward. The fact that here we cannot use the floating point calculation makes everything trivial and not much accurate. Anyway convert this strategy into an accurate one using floating point it's easy as well.