Soln is right. Just make sure with interviewer on what he is expecting. if double then use Double.parseDouble(string s) or float.ParseFloat(String s).
1
Utilisateur anonyme
5 nov. 2012
I think a good solution can be something like this:
String pattern = "[0-9,.]+";
return (number.matches(pattern));
1
Utilisateur anonyme
8 juil. 2011
public static boolean validate(String s)
{
try
{
int i = Integer.parseInt(s);
}
catch(NumberFormatException e)
{
return false;
}
return true;
}
1
Utilisateur anonyme
17 juin 2012
above solution is wrong as it never said the number is an int, it can be flot, decimal, double or int.
Utilisateur anonyme
7 janv. 2013
if we are going with regex
mihir is on the right track
make sure you put (\\+|-) before [0-9]+ since - or + should be allowed also to allow decimal numbers follow this with (\\.)?[0-9]+