Search a target number in a Rotated Sorted Array.

Question

hivehive · Accepted Answer

public int search(int[] nums, int target) {
        int start = 0;
        int end = nums.length - 1;
        while (start = nums[start]) {
                    end = mid - 1;
                } else {
                    start = mid + 1;
                }
            } else {  //5 6 7 1 2 3 4, 6
                if (target > nums[mid] && target <= nums[end]) {
                    start = mid + 1;
                } else {  //
                    end = mid - 1;
                }
            }
        }
        return -1;
    }

Really? · Answer

To answer the Pi question- I will first turn the calculator on, press 22, then press '/', then 7, then '='.
Then I will test for edge cases where calculator's buttons may not have been pressed properly. -_-

Utilisateur anonyme · Answer

Binary search

uber-grow-up · Answer

I would like to slap your interviewer for asking this question in an interview: "How do you calculate PI, if I just give you a calculator."

Definitely he/she don't know what is "problem solving" in software engineering.

Btw, I work for Amazon.

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