Analyze a horrible JavaScript function to determine the problems. Essentially a nasty for loop with a setTimeout inside that did a console.log of the loop iterator's value.

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Utilisateur anonyme · Accepted Answer

Trick question of course, the setTimeout makes it so that the iterator has gone to the full value of N by the time the setTimeout fires, so all statements print the same value. The fix?  Use closures/self executing function to capture the value when the setTimeout is first set so that it maintains the correct corresponding value.

Utilisateur anonyme · Answer

Just add a Closure to it.

for (var j=0; j< 10; j++) {
   (function(j) { 
       return setTimeout[function() { console.log(j); }, 100) 
    })(j);
}

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